Nov 22, 2015 · How do Javascript Math.max and Math.min actually work? Asked 10 years, 3 months ago Modified 4 years, 3 months ago Viewed 16k times

max = testArray[i]; } } MDN solution The official MDN docs on Math.max() already covers this issue: The following function uses Function.prototype.apply () to find the maximum element in a numeric array. …

The reason why your code doesn't work is because Math.max is expecting each parameter to be a valid number. This is indicated in the documentation as follows: If at least one of arguments cannot be …

Sep 13, 2009 · Math.max(num1, Math.max(num2, num3)) As @CMS points out, JavaScript specifically allows an arbitrary number of parameters to Math.max:

Nov 15, 2019 · I want to select the biggest number in an array of objects, so for example, I want to get the x property that holds the largest number (in this example, maximum should be 200): var myArr = …

And for Math.max it's the same; all numbers that are larger than negative infinity should be the biggest if there are no bigger. So for your first example: Math.min(5) where 5 is smaller than positive infinity …

Sep 6, 2016 · Most answers here use apply or the spread operator ... to call the Math.max function with all the elements of an array as parameters. For large arrays it is safer to use reduce:

Math.max.apply(Math,list) Invokes a Math.max function with Math object to be used as a this reference in the function implementation (body) and list to be passed as an arguments.

So it's number when number > 1, and it's 1 when number <= 1. i.e. it is always greater than or equals to 1, no matter what number is, as long as number is numeric (Math.max can return NaN when number …

Sep 16, 2015 · Math.max(a, Math.min(x, b)) The issue I am having is that math.max looks as if it returns math.min in this formula. Does that not destroy the cause of max or am I missunderstanding …